The current i_o = 8A, Voltage v_g = 480 V.
a) Find the value of R.
b) Find the power supplied by the voltage source.
The Attempt at a Solution
Well, I noted both pairs of series resistors, to make the calculations a little simpler, and what I ended up with was this delta-Y or Y-delta formation (not sure, just saw something about it on a post here while digging around).
I figured that the voltage drops across each resistor MUST equal 480V, so I started setting up the equations, but I'm not sure if I really did it right.
There were 5 other currents which are not given. I dubbed the one passing through 'R' to be I3, the one passing through the 4ohm resistor to be I1, the one passing through the 20ohm resistor series as I2, and the one passing through the 10ohm resistor as I4. I dubbed the current flowing through the voltage source to be Is.
Doing what I hoped was an accurate KVL of that freakin triangle thing, as well as some KCLs, I came up with 5 equations, with a total of 6 variables including the Resistor....
At this point I'm pretty sure I've done something wrong, but I'm not sure what?
Part B should be easy once I find Part A.