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Circuit- Solving for Req

  1. Sep 12, 2010 #1
    1. The problem statement, all variables and given/known data

    Solve for Req



    3. The attempt at a solution

    The resistors in the middle can be added to total of 5 ohms. So then then 5v +5ohms = 10 ohms

    Then they are all in series 1.5+10+ 1.5= 12.5? What I don't understand is what do i do with
    Rx? or 12.5 is Req?

    Here is the circuit:
     

    Attached Files:

    Last edited: Sep 12, 2010
  2. jcsd
  3. Sep 12, 2010 #2
    hmm. just an fyi: i don't see any circuit beneath your promise for the circuit
     
  4. Sep 12, 2010 #3
    Sorry about that.
     
  5. Sep 12, 2010 #4
    you are correct that the middle branch can be replaced with 5 ohms. However, it does not add in series with the other 5 ohm resistor to its right. instead, they add in parallel. Then that parallel combination adds in series with the 1.5 and 1 ohm resistors.
     
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