Circuit with Dependent Current Source

Click For Summary

Homework Help Overview

The discussion revolves around a circuit problem involving a dependent current source and the application of nodal analysis. Participants are attempting to analyze the circuit setup and the behavior of the current source.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Kirchhoff's Current Law (KCL) at a specific node but encounters discrepancies in the expected results. Some participants question the validity of the circuit setup, particularly the connection of ammeters, and seek clarification on how to determine the current through the current source.

Discussion Status

The discussion is active, with participants exploring different interpretations of the circuit setup. There is a focus on identifying potential errors in the configuration and understanding the implications of the ammeter's placement. No consensus has been reached regarding the correct approach or interpretation.

Contextual Notes

Participants note that the original problem is derived from a university exercise list, and there is uncertainty about the accuracy of the circuit diagram as presented in the source material.

wk1989
Messages
32
Reaction score
1

Homework Statement


I'm not sure how to solve this question, the method you're supposed to use is nodal analysis.

Homework Equations





The Attempt at a Solution


I tried to use KCL at node A, so I have
Code:
(12-Va)/8 - 3Va =0

Once I solved Va, the current is 3*Va. However, I'm not getting the right answer which is supposed to be -6 A.

Any help would be appreciated, thanks!
 

Attachments

  • Untitled.jpg
    Untitled.jpg
    9 KB · Views: 530
Physics news on Phys.org
The setup makes no sense. You don't connect ammeters in parallel with circuit elements, you connect them in series.

Are you sure this is how the diagram appears in your book?
 
This was on a list of exercise problems from a university website, but ignoring that, how would you find the current through the current source?
 
wk1989 said:
how would you find the current through the current source?

That is precicely why the setup makes no sense. If the ammeter truly is reading the current through the current source, then you don't need to calculate the current. You just read it! But that ammeter cannot possibly be reading the current through the current source, because it's connected wrong.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
5
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K