Circular accelaration with increasing velocity?

AI Thread Summary
The discussion centers on calculating the force applied to an object moving along a circular arc with increasing velocity. The object starts from rest, accelerates along a 45-degree arc with a radius of 2 meters, and reaches a speed of 7 m/s before release. The total force required combines centripetal force, which acts radially inward, and tangential force, which increases the object's speed. The radial unit vector, represented as {Rho}, indicates the direction of the centripetal force, while the tangential force is necessary for acceleration along the arc. Understanding these forces is crucial for solving the problem accurately.
Denken
Messages
19
Reaction score
0
circular accelaration with increasing velocity?

Homework Statement


Object starts at rest at an angle of 0 degree's. the object is accelerated along a 45 degree arc with a radius of 2 meters to a speed of 7m/s at which point it is released. the object has a mass of .3 Kg. What is the equation for the force applied along the arc?


Homework Equations



circular accel. = V[2][/r] and other kinematics and derivatives and anti-derivatives

The Attempt at a Solution


way more work than i am going to put on here, but in the end i got a jerk function of 960.4/pi
... not fun
 
Physics news on Phys.org


To keep it in a circle you need a certain force. To accelerate it tangentially you need another. Superpose them to get the total force.

\vec{F}=-\frac{mv^{2}}{R}\hat{\rho}+F_{tan}\hat{\theta}

Then use basic kinematic equations with the information given to find the tangential force. Then it's just a matter of getting the magnitude, which we expect to be time dependent due to the centripetal contribution.
 


just a couple questions on that ... what does the {Rho} represent and why is it Ftan?
 


The rho is the radial unit vector. Centrifugal forces push the mass out; in order for it to stay in a circle there needs to be an equal and opposite force pulling it in. This is what the force in the negative rho direction represents.

Mathematically,

\hat{\rho}=cos(\theta)\hat{x}+sin(\theta)\hat{y}

As for the other component of the force it is directed tangentially to the circle because it increases the tangential speed of the mass.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top