Circular motion angular velocity

AI Thread Summary
The discussion focuses on calculating the angular velocity of a particle moving in a plane relative to a reference point. A common technique involves taking the component of the particle's velocity that is perpendicular to the line connecting it to the reference point and dividing this by the distance between them. This method is linked to the circular motion analogy where angular velocity is derived from the relationship v = rw. Participants confirm that the projection of the velocity onto a circular path represents the arc length, which helps in determining the angle. Overall, the approach to finding angular velocity through velocity components and distance is clarified and validated.
Abhishekdas
Messages
198
Reaction score
0
Circular motion...angular velocity...

Homework Statement


This is a general question i have...Lets say a particle is moving in a plane (in any arbitrary way may or maynot be following any equation)...Now we are told to find the angular velocity of the particle with respect to a reference point at some instant...lets say you have the velocity vector of the particle and the position vector of the particle with respect to the reference point(or simply the distance between them).

Homework Equations





The Attempt at a Solution


A technique i came across(which i guess is common) is to take the component of the velocity which is perpendicular to the line joining the point and the particle and then dividing it by the distance between them.

Now does this method comes from analogy with circular motion where v=rw? I am not totally convinced by this method and i don't understand this properly...So please help...
 
Physics news on Phys.org
Hi Abhishekdas! :wink:
Abhishekdas said:
A technique i came across(which i guess is common) is to take the component of the velocity which is perpendicular to the line joining the point and the particle and then dividing it by the distance between them.

Now does this method comes from analogy with circular motion where v=rw? I am not totally convinced by this method and i don't understand this properly...So please help...

Yes, that's fine …

angular velocity = angle per time,

and to find the angle you're only interested in the projection of the velocity on a circle, ie the component of the velocity perpendicular to the line joining the point and the particle …

so you find that projection (an arc of a circle), then divide by the radius to get the angle :smile:
 


Hey thanks tiny-tim... i think i am kind of getting it...
Is it like the actual velocity is the hypotenuse of a right angled triangle and the base ie the projection is approximated as the arc and then it iss arc = r*d(theta)...
Am i thinking correctly?
 
Yes that's right …

component and projection are the same thing. :smile:
 


ya...Thanks...got it...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top