Circular Motion - Banked Curve

AI Thread Summary
To determine the banking angle for a curve with a radius of 50 m at a speed of 40 km/h without friction, the initial calculations were based on incorrect speed units. After converting the speed to 11.111 m/s, the formula tan θ = v²/(r*g) was applied correctly. This yielded a value of approximately 0.251, leading to a final angle of 14.11 degrees when using the arctangent function. The revised calculations confirm the correct approach and answer. The discussion highlights the importance of unit conversion in physics problems.
Iser
Messages
4
Reaction score
0

Homework Statement



Designing an on ramp for the 401 the engineer wants cars to be able to make the turn with a radius of 50 m while traveling 40km/hr in conditions with no friction. What angle must he bank the curve at to make this possible?

Homework Equations



FR = (m)(aR)
FR = (m)(v2)/(r)

The Attempt at a Solution



I first started by drawing a diagram and noting the values I have for the question which are the velocity (40 km/h) and the radius (50 m). The value I we're looking for in the question is the angle the bank makes.

I first know FN(Sin θ) = (m)(v2)/R

which I can then isolate FN through which becomes

FN = (m*g)/(cos θ)Since in the actual equation has no movement in the y-axis it is:
FNsinθ = m * v2/r

Then I sub in the FN I got from the previous equation and sub it into this one getting:

(m*g/cos θ)(sin θ) = m * v2/r

which then simplifies into:

tan θ = v2/r*g

I then put in the original values I had into the equation and got 3.26 then I put 3.26 into the tan-1 thing in the calculator and got 73o degrees.

Is my answer and thought process correct?
 
Physics news on Phys.org
Iser said:
I then put in the original values I had into the equation and got 3.26 then I put 3.26 into the tan-1 thing in the calculator and got 73o degrees.

Is my answer and thought process correct?
Your thought process is perfect but your answer is not. (Convert the speed to standard units. :wink:)
 
Doc Al said:
Your thought process is perfect but your answer is not. (Convert the speed to standard units. :wink:)

Converted 40 km/h to 11.111 m/s.

Now I input the following into the formula:

tan θ = (11.1 m/s)2/(50)(9.8)

Which equals 0.2514489...

I then input that into the tan-1 function into the calculator and get:

14.11o degrees

Is this correct?
 
Iser said:
Converted 40 km/h to 11.111 m/s.

Now I input the following into the formula:

tan θ = (11.1 m/s)2/(50)(9.8)

Which equals 0.2514489...

I then input that into the tan-1 function into the calculator and get:

14.11o degrees

Is this correct?
Looks good!
 
  • Like
Likes 1 person
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top