Conservation of Energy in a Block-Cylinder System

AI Thread Summary
In a block-cylinder system, a 3.35 kg block attached to a string unwinds from a 1.22 kg hollow cylinder as it falls 1.11 m. The gravitational potential energy of the block is converted into both translational kinetic energy of the block and rotational kinetic energy of the cylinder. Energy conservation principles apply, ensuring that the total energy remains constant throughout the motion. The discussion clarifies that the block is not in free fall due to its connection with the cylinder. Ultimately, the problem is resolved with the correct application of energy conservation.
shashusad
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I have this question on my Circular motion assignment, but its somehow connected to free fall. I'm unable to picturize the situation mentioned in question...

A 3.35 kg block is attached to a string that is wrapped around a 1.22 kg, 5.03 cm diameter hollow cylinder that is free to rotate on an axel through the center. The block is released 1.11 m above the ground. What is the speed of the block as it hits the ground?
 
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shashusad said:
I have this question on my Circular motion assignment, but its somehow connected to free fall. I'm unable to picturize the situation mentioned in question...

A 3.35 kg block is attached to a string that is wrapped around a 1.22 kg, 5.03 cm diameter hollow cylinder that is free to rotate on an axel through the center. The block is released 1.11 m above the ground. What is the speed of the block as it hits the ground?
As the block falls what happens to the cylinder? What's conserved?

(The block is not in free fall--it's connected by the string to the cylinder.)
 
The energy will be conserved. The gravitational potential energy of the block gets converted into tranlational kinetic energy of the block and rotational kinetic energy of the cylinder. I got the answer... Thanks a lot Doc Al !
 

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