Circular motion Involving Static Friction

AI Thread Summary
To determine how far a coin can be placed from the center of a turntable rotating at 45.0 rpm without slipping, the coefficient of static friction (0.1) and the concept of centripetal force are essential. The centripetal force required to keep the coin in circular motion is provided by the static friction between the coin and the turntable. The equation F = μsN relates the frictional force to the normal force, which is equal to the weight of the coin. By analyzing these forces, one can calculate the maximum radius at which the coin can remain stationary on the turntable. Understanding the balance of forces is crucial for solving this problem effectively.
Jtappan
Messages
95
Reaction score
0

Homework Statement



A coin is placed on a turntable that is rotating at 45.0 rpm. If the coefficient of static friction between the coin and the turntable is 0.1, how far from the center of the record can the coin be placed without having it slip off?
______ cm


Homework Equations



F = mew(s)N

The Attempt at a Solution



I have no idea how to solve this one...which information is implied? Any help?
 
Physics news on Phys.org
The coin is moving in a circle right? Which means that there is some sort of centripetal force acting on the coin. What force is it?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Direction of static friction between a vehicle and circular dome
Replies
9
Views
2K
Why is the direction of kinetic/static friction up a ramp?
Replies
7
Views
1K
Coin on a turntable problem in a noninertial frame
Replies
12
Views
2K
Direction of friction in circular motion
Replies
5
Views
3K
Motion when Kinetic Friction is more than Static Friction
Replies
10
Views
2K
Rolling without slipping problem
Replies
42
Views
3K
Static friction rotating an object
Replies
10
Views
2K
Static friction and a rotating object
Replies
14
Views
2K
Max static friction witout mass or normal force?
Replies
9
Views
2K
Rotational work done by static friction?
Replies
5
Views
4K

Hot Threads

Recent Insights

Back
Top