Circular Motion: Location & Speed at t=1s

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SUMMARY

The discussion focuses on calculating the location and speed of a reference dot on a computer disk with an 8.0 cm diameter after 1 second of acceleration and coasting. The disk accelerates to an angular velocity of 1480 rpm, which converts to approximately 2960π rad/sec. The initial angle is set at θ = +45°, and the formula used to determine the angle covered during acceleration is θ = θ₀ + ω₀t + ½αt². The final speed of the reference dot is confirmed to be 6.28 m/s.

PREREQUISITES
  • Understanding of angular velocity and linear velocity relationships (v = rw)
  • Familiarity with rotational kinematics equations
  • Basic knowledge of radians and degrees conversion
  • Ability to perform calculations involving angular acceleration
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  • Study rotational kinematics in-depth, focusing on angular displacement and acceleration
  • Learn about converting between angular velocity (rpm) and radians per second
  • Explore the relationship between linear speed and angular speed in circular motion
  • Practice problems involving circular motion to solidify understanding of the concepts
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This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the principles of circular motion and rotational dynamics.

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1. A computer disk is 8.0 cm in diameter. A reference dot on the edge of the disk is initially located at θ = +45°. The disk accelerates steadily for second, reaching 1480 rpm, then coasts at steady angular velocity for another second. What are the location and speed of the reference dot at t = 1 s?

2. v=rw


3. i already got the 6.28 m/s for speed. and i thought since i have speed i can just do v=rw to get w and then draw a diagram to get the area under the curve. After i got the area just use delta theta/ 2pi=revolution. then minus the whole number and take the decimal to divide by 360 then plus 45 right? but appreantly i am wrong
 
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xstetsonx said:
1. A computer disk is 8.0 cm in diameter. A reference dot on the edge of the disk is initially located at θ = +45°. The disk accelerates steadily for second, reaching 1480 rpm, then coasts at steady angular velocity for another second. What are the location and speed of the reference dot at t = 1 s?

2. v=rw3. i already got the 6.28 m/s for speed. and i thought since i have speed i can just do v=rw to get w and then draw a diagram to get the area under the curve. After i got the area just use delta theta/ 2pi=revolution. then minus the whole number and take the decimal to divide by 360 then plus 45 right? but appreantly i am wrong

We assume it is at rest at t=0 and accelerates until t = 1s at which time its speed [itex]\omege =2960\pi[/itex] rad/sec. To find the angle it covers in that first second, use:

[tex]\theta = \theta_0 + \omega_0t + \frac{1}{2}\alpha t^2[/itex]<br /> <br /> AM[/tex]
 
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