Circular Motion: Minimum Radius for Safe Fighter Pilot Maneuvers

AI Thread Summary
To determine the minimum radius for safe fighter pilot maneuvers, the normal force on the pilot must not exceed 7G's during a vertical pullout from a dive at 320 m/s. The equation used is 7mg = mv²/r, leading to the calculation of radius r = v²/(7g). Substituting the values, r is found to be approximately 1492.7 meters. The discussion clarifies that G-force is not the same as friction but represents the force felt by the pilot due to acceleration. Understanding these concepts is crucial for calculating safe maneuvering parameters in aviation.
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"A fighter pilot dives his plane toward the ground at 320 m/s. He pulls out of the dive on a vertical circle. What is the minimum radius of the circle, so that the normal force on the pilot by his seat never exceeds 7G's?"


Im stuck... I've tried different things with equations like 'friction=(mass X volume^2)/radius but I am not getting much of anywhere :mad:
 
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7mg=\frac{mv^2}{r}
7rg=v^2
7r(9.8m/s^2)=(320m/s)^2
r=1492.7m
 
hrmm u just use the 7 as the friction coefficient? :confused: I didn't realize that, heh, i feel stupid now.

Ok.. yea.. i guess "g's" would be friction heh, k guess i was asleep :-p

thanks tho
 
"g" is not friction. Think about it like this...when you're in a car and you're accelerating, you feel a force pushing back on you. That force is the G-force. One G is equal to your weight (mg). So, 7 g is 7mg.
 

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