Circular Motion of a car on a curve

AI Thread Summary
To determine the coefficient of static friction for a car on a perfectly banked curve, the discussion highlights the need to consider both the banking angle and the centripetal force required for circular motion. The initial calculations suggest a coefficient of static friction of 10.5, which is deemed excessively high. Participants clarify that a perfectly banked curve allows for the necessary centripetal force to be provided by the normal force, reducing reliance on friction. The concept of "perfectly banked" implies that at the optimal speed of 75 km/h, no lateral frictional force is needed to maintain circular motion. Understanding these dynamics is crucial for accurately calculating the required coefficient of static friction at higher speeds.
FossilFew
Messages
15
Reaction score
0
Hello - I'm having doubts about this approach. Thanks in advance!

If a curve with a radius 88m is perfectly banked for a car traveling 75 km/h what must be the coefficient of static friction for a car not to skid when traveling at 95 km/h?

95km/h = 26.4m/s
75km/h = 20.8 m/s

Fr=ma (radial a)
v^2/gr=Us
Us= (95^2/(9.81* 88) = 10.5 ( This seems too large)
 
Physics news on Phys.org
How are you taking into account the banking of the curve? Don't forget that a component of the normal force will provide some of the required centripetal force. What do you think "perfectly banked" means?
 
We just got into circular motion so being a circular motion newbie I can only give you a newbie answer. My interpretation of perfectly banked means there is a force pushing the car towards the center of the track. I'm not sure how to use that explanation (assuming it is correct) into an equation.

Thanks!
 
FossilFew said:
We just got into circular motion so being a circular motion newbie I can only give you a newbie answer. My interpretation of perfectly banked means there is a force pushing the car towards the center of the track. I'm not sure how to use that explanation (assuming it is correct) into an equation.

Thanks!
Perfectly banked means that the driver of the vehicle does not feel like s/he is being pushed sideways relative to the seat. Equivalently, it means there is no force making the tires slide up or down the track. What does this tell you about the force of friction when the car is traveling at the "perfect bank" speed of 75 km/h?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Banked roads -- circular motion and gravitation
Replies
11
Views
2K
Banked Circular Motion with Static Friction
Replies
1
Views
2K
Radial & Tangential Acceleration of a Car at Indianapolis 500 | Physics Solution
Replies
7
Views
4K
Designing a Banked, Circular Highway Exit | Help with Homework
Replies
9
Views
2K
Banked Curve-Determine smallest static coefficient of friction
Replies
9
Views
4K
Banked Curve perfectly banked
Replies
4
Views
8K
Find the Coefficient of friction on a banked curve.
Replies
9
Views
6K
What is the Needed Coefficient of Static Friction for a Car on a Banked Curve?
Replies
16
Views
2K
Cars rounding a slippery banked corner in the rain
Replies
20
Views
3K
Centripetal Force on an incline + Fricktion
Replies
4
Views
4K

Hot Threads

Recent Insights

Back
Top