saltrock
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Hi guys.what do you think of the answers i have got for the questions below.If you think i have made any mistakes please do say so.I think my answers are weird,
a) A space station orbits the Earth in every 91 mins .calculate the angular speed of the space station
ans) 91/60 times 2pie=9.52 radians
b)The space station orbit is 210 km above the surface of the Earth which has the radius of 6370 km.Fine the acceleration of the space station.
ans) a=rw(squared)
r=(6370000 + 210000)m
w=9.52(from above)
Therefore a= 6.2 times 10^7
I thin the value of a is toooooooo large...I am confused here
c)A box of mass 4.1 kg is located inside the space station.What is the size and the direction of the resultant force acting on the box in the space station?
Direction of Resultant force=towards the earth
size=F=ma=4.1 times 6.2 times 10^7=2.5 times 10^8...I think this is incredbly a very large force...I have got a feeling that all my answers are wrong..Plz help me out!
a) A space station orbits the Earth in every 91 mins .calculate the angular speed of the space station
ans) 91/60 times 2pie=9.52 radians
b)The space station orbit is 210 km above the surface of the Earth which has the radius of 6370 km.Fine the acceleration of the space station.
ans) a=rw(squared)
r=(6370000 + 210000)m
w=9.52(from above)
Therefore a= 6.2 times 10^7
I thin the value of a is toooooooo large...I am confused here
c)A box of mass 4.1 kg is located inside the space station.What is the size and the direction of the resultant force acting on the box in the space station?
Direction of Resultant force=towards the earth
size=F=ma=4.1 times 6.2 times 10^7=2.5 times 10^8...I think this is incredbly a very large force...I have got a feeling that all my answers are wrong..Plz help me out!
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