Circular motion related to linear motion

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SUMMARY

The discussion centers on determining the velocity of point A as block B moves upward at a constant speed of 2 m/s. The correct answer is option (a), with a velocity of 2.31 m/s at an angle of 60 degrees to the horizontal. The reasoning involves understanding that A and B share the same speed, and the velocity vector of A is tangent to the semicircular slot, necessitating the use of Pythagorean theorem to confirm the magnitude exceeds 2 m/s.

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  • Understanding of circular motion dynamics
  • Knowledge of vector components and their calculations
  • Familiarity with Pythagorean theorem
  • Basic geometry related to angles and tangents
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  • Study the principles of circular motion in physics
  • Learn about vector decomposition and addition
  • Explore the application of the Pythagorean theorem in physics problems
  • Investigate the relationship between linear and angular velocities
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Students studying physics, particularly those focusing on mechanics and motion, as well as educators seeking to clarify concepts of circular motion and vector analysis.

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Homework Statement


As block B moves upward with constant speed 2 m/s, pin A glides through the semicircular slot. At the position shown, determine the velocity of A.

a. 2.31, angle 60o
b. 2.00, angle 60o
c. 1.00, angle 0o
d. 1.89, angle 30o

circularmotion.jpg



Homework Equations


Not sure


The Attempt at a Solution


A and B will have the same speed, so the answer is b (the angle is 60o to the horizontal) ?

Thanks
 
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The velocity vector of A is going to be tangent to the circle, so its angle relative to the horizontal will be 60 degrees (you can check this with some simple geometry). We also know that the vertical compontent of this vector is 2 since it is given by object B. By pythagoras the magnitude of the vector must be greater than 2. Therefore, the answer must be (a).
 
Hi Vykan12

Oh I get it. Thanks a lot Vykan12 :smile:
 

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