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Circular motion , the loop the loop

  1. Jan 21, 2016 #1
    1. The problem statement, all variables and given/known data
    The loop-the-loop machine has radius R of 18m
    (a) What is the minimum speed at which a cart must travel so that it will safety loop the loop
    (b) what will the speed at the top be in this case

    2. Relevant equations
    Centipetal force = m*v^2/r
    Kinetic and potential energies = (1/2) m*v^2 and mgh respectively


    3. The attempt at a solution
    (a) equating weight and centripetal force and then solving for v I got an answer for velocity of 13.2 but the actual answer is 30
    (b) based on (a) calculate the velocity using energy equations
    (1/2)m×v^2 = mgh + (1/2) m×v^2
     
  2. jcsd
  3. Jan 21, 2016 #2

    Doc Al

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    Staff: Mentor

    I believe (a) is asking for the speed at the bottom. (Solve (b) first.)
     
  4. Jan 21, 2016 #3
    I get what it's asking just not how to get the answer
     
  5. Jan 21, 2016 #4

    Doc Al

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    Staff: Mentor

    You solved part (b).
     
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