Circumference of Circle with Uncertainty

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Homework Help Overview

The discussion revolves around calculating the circumference of a circle while considering the uncertainty in the measured radius. The original poster presents two methods for incorporating uncertainty into their calculations, with a radius of r=7.3 ± 0.2 cm.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the circumference using two different methods, questioning the validity of each approach and the treatment of significant figures in their final answer.

Discussion Status

Some participants suggest that the first method is preferable, emphasizing the importance of understanding the calculus behind the error propagation. There is acknowledgment of the original poster's concern regarding significant figures, with some participants affirming that the final answer is correct.

Contextual Notes

One participant cautions against rounding errors down, indicating that this could misrepresent the accuracy of the measurement. They suggest a different way to express the final answer that includes a more accurate representation of the uncertainty.

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Homework Statement


Calculate the circumference (including uncertainty) of a circle whose measured radius is r=7.3 ± 0.2cm.

2.Relevant equations & 3.The attempt at a solution

- Circumference of circle --> C = 2πr = 2π7.3 = 45.87 cm

- Exact constant error propagation --> z = kx

- Limit Error --> δz = kδx

- Therefore, δC = 2π(0.2 cm) = 1.257 cm

Final Answer = 46 ± 1 cmOR Should I be going about it like this:

- Circumference of circle --> C = 2πr = 2π7.5 = 47.124 cm = 47 cm

- Circumference of a circle --> C = 2πr = 2π7.1 = 44.611 cm = 45 cm

- Final Answer 46 ± 1 cmI was discussing this with someone else. I did it the first way and they did it the second way.

Also, my final answer has the correct significant figures right?
 
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You should do it the first way. Bracketing the calculated value with the minimum and maximum values using the given uncertainty is for people who are not conversant with calculus and do not understand where ΔC = 2πr Δr comes from. Yes, your final answer has the correct sig. figs.
 
kuruman said:
You should do it the first way. Bracketing the calculated value with the minimum and maximum values using the given uncertainty is for people who are not conversant with calculus and do not understand where ΔC = 2πr Δr comes from. Yes, your final answer has the correct sig. figs.
Thank you! That's what I thought as well :)
 
Word of warning: You typically should not round errors down. This overrepresents the accuracy that you have. The typical thing to do when you have an error whose first non-zero digit is 1 or 2 is to include another digit to also avoid overstating the error.

The number of significant digits is not very relevant when you include the errors, the entire point of significant digits is that it is kind of a poor man's error analysis - letting you get a feeling for the kind of accuracy that you have from the number of digits you have included - but this is obsolete when you have the actual error!

In this case, I would answer 45.9±1.3 cm.
 

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