Classical Mechanics: Lagrangian of a falling yo-yo

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SUMMARY

The discussion focuses on deriving the Lagrangian for a yo-yo system with a moving support, specifically analyzing the equations of motion and energy expressions. The Lagrangian is defined as L = T - V, where T represents kinetic energy and V represents potential energy. The participant successfully derived Lagrange's equation, yielding the result \(\dot{}\dot{\varphi} = \frac{2}{3} \frac{g}{a}\). The relationship between the yo-yo's vertical position and the upward displacement of the support, h(t), is critical for understanding the system's dynamics.

PREREQUISITES
  • Understanding of Lagrangian mechanics and generalized coordinates
  • Familiarity with kinetic and potential energy equations
  • Knowledge of rolling motion and the condition for rolling without slipping
  • Basic calculus, particularly in relation to derivatives and motion equations
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  • Study the derivation of Lagrange's equations in classical mechanics
  • Explore the concept of rolling without slipping in detail
  • Investigate the implications of moving supports on dynamic systems
  • Learn about energy conservation principles in mechanical systems
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Homework Statement


A uniform circular cylinder (a yo-yo) of radius a and mass M has a string wrapped around
it that can unwind without slipping. The yo-yo moves in a vertical straight line and the
straight part of the string is vertical as well. The other end of the string is fastened to a
support that has upward displacement h(t) at time t. Here h(t) is a prescribed function, not
a degree of freedom.
a. Take the rotation angle φ of the yo-yo as a generalized coordinate and find Lagrange’s equation.
b. Find the acceleration of the yo-yo. What must the support’s acceleration h(t) be so
that the centre of the yo-yo can remain at rest?
c. Suppose the system starts from rest. Find an expression for the total energy E = T+V at time t, in terms of h and h.

Homework Equations


L=T-V
T=\frac{1}{2}M\dot{y}^{2}+\frac{1}{2}I\dot{\varphi}^{2}
Defining downwards as my positive direction: V=-Mgy
Rolling without slipping ---> a\dot{\varphi}=\dot{y}
Since the support is moving upwards given by (h(t)) ---> y=\widetilde{y}-h(t) where \widetilde{y}= the distance between the yo-yo and the support at time t. So, \dot{y}=\dot{\widetilde{y}}-\dot{h(t)}

The Attempt at a Solution


With these equations and treating \varphi as my generalized coordinate, it's easy to obtain the Lagrange's equation of motion for this system. I get \dot{}\dot{\varphi}=2/3*g/a

Now for part b) of the question, I have \dot{}\dot{y}=\dot{}\dot{h}. If this is correct, I can figure this out using the without slipping equation above.
From here on before starting part c), I am wondering why the Lagrange's equation I got is independent of h(t) (i.e its the same as if the support was fixed). And if its wrong, it has to do something with the relation between y and h(t). Any help is apprecaited
 
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