Clausius-Clapeyron equatioin's constant for methanol

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The Clausius-Clapeyron equation is expressed as lnP = A - C/T, where A and C are constants that vary based on the specific material and conditions like temperature and pressure. For methanol, the values of A and C are not provided in the discussion, but they can be determined through experimental data or literature. The equation indicates a linear relationship between log P and 1/T, which can be useful for interpolating pressure values at specific temperatures. For example, knowing pressure data for water at 5 K increments allows for interpolation of pressure at a non-standard temperature. Understanding these constants is essential for accurately applying the Clausius-Clapeyron equation to methanol.
connard
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Hi everyone!
I'm searching for the constants in Clausius-Clapeyron equation

lnP=A-C/T

I'ld like to know the value of A and C. (for Pressure unity is hPa and Temperature is K )

Thanks
 
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connard said:
Hi everyone!
I'm searching for the constants in Clausius-Clapeyron equation

lnP=A-C/T

I'ld like to know the value of A and C. (for Pressure unity is hPa and Temperature is K )

Thanks
They depend on the material under consideration, and on conditions like temperture and pressure. For water you could look at some steam tables. What the equation says is that log P and 1/T are linear as a 1st approximation. The equation can be used to interpolate a data set. Ie you know P(T) for water in 5 K increments from 273 to 373 and want to know P(300.62).
 
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