Closed and Exact Forms on 2-Torus: Solving for Global Definitions and Exactness

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Homework Statement



Now consider a 2-torus ## S_1 × S_1## and a coordinate patch with coordinates ## (\alpha_1, \alpha_2)## such that ## 0 < \alpha_i < 2 \pi##. Let us introduce in this patch a 1-form of the type:
$$\omega = (A + B\alpha_2 + C sin(\alpha_2 ) + D cos(2\alpha_1 + \alpha_2 ))d\alpha_1 + \phi(\alpha_1 , \alpha_2 )d\alpha_2$$

a) Try to determine the possible values of the function ##\phi(\alpha_1 , \alpha_2 )## so
that the form ##\omega## is closed.

b) For what values of A, B, C and D is the closed form globally
defined?

c) For what values of A, B, C, D and ##\phi## is the form exact?

Homework Equations



A form is closed when satisfies: ##d\omega=0##

The necessary and sufficient condition for a closed r-form ##\omega## to be exact is that for ##b_r## independent cycles in ##C_a \in H_r## the periods vanish: $$ \int_{C_a} \omega = 0$$

The Attempt at a Solution



[/B]
a) Using the equation of the exterior derivative and knowing that ##d\omega = 0## I wrote:

$$ 0 + (\frac{\partial B\alpha_2}{\partial \alpha_1}d\alpha_1 + \frac{\partial B\alpha_2}{\partial \alpha_2}d\alpha_2)\wedge \alpha_1 + ... = \Bigg( \frac{\partial \phi (\alpha_1, \alpha_2)}{\partial \alpha_1}d\alpha_1 + \frac{\partial \phi (\alpha_1, \alpha_2)}{\partial \alpha_2}d\alpha_2 \Bigg) \wedge d\alpha_2$$

Using the Poincarè lemma ##d^2=0## and the relation ## dx^i \wedge dx^j = -dx^j \wedge dx^i ## I finally obtained:
$$
-B d\alpha_1 \wedge \alpha_2 = \frac{\partial \phi (\alpha_1, \alpha_2)}{\partial \alpha_1}d\alpha_1 \wedge \alpha_2 $$

Not sure how to resolve this, maybe: ## \phi (\alpha_1, \alpha_2) = -2\pi B ## ?

b) Do not know... it is when the coord charts are defined for all values of a parameter? Sorry I do not know.

c) No idea. I get lost when read the de Rham cohomology theory, etc.
 
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Breo said:
a) Using the equation of the exterior derivative and knowing that ##d\omega = 0## I wrote:

$$ 0 + (\frac{\partial B\alpha_2}{\partial \alpha_1}d\alpha_1 + \frac{\partial B\alpha_2}{\partial \alpha_2}d\alpha_2)\wedge \alpha_1 + ... = \Bigg( \frac{\partial \phi (\alpha_1, \alpha_2)}{\partial \alpha_1}d\alpha_1 + \frac{\partial \phi (\alpha_1, \alpha_2)}{\partial \alpha_2}d\alpha_2 \Bigg) \wedge d\alpha_2$$

Using the Poincarè lemma ##d^2=0## and the relation ## dx^i \wedge dx^j = -dx^j \wedge dx^i ## I finally obtained:
$$
-B d\alpha_1 \wedge \alpha_2 = \frac{\partial \phi (\alpha_1, \alpha_2)}{\partial \alpha_1}d\alpha_1 \wedge \alpha_2 $$

What happened to the terms involving C and D?

b) Do not know... it is when the coord charts are defined for all values of a parameter? Sorry I do not know.

I'm not 100% positive what the question is asking for, but if \alpha_1 and \alpha_2 are angles, then that means that \alpha_1 = 0 is the same angle as \alpha_1 = 2 \pi, and similarly for \alpha_2. That means that a globally defined function should be periodic in \alpha_1 and \alpha_2.

c) No idea. I get lost when read the de Rham cohomology theory, etc.
A 1-form \omega is exact if there is a function f(\alpha_1, \alpha_2) such that \omega = d f. So you're just being asked when it is possible to find such an f.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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