I Closing the Gap: The Evolution of CMS at CERN

YoungPhysicist
Insights Author
Messages
350
Reaction score
203
In this picture of CMS, there is a huge gap between the two sides. There is no way that the collision occur directly in midair right?

So is the gap already been sealed? ( which means the picture was taken before it started to operate) Or I am completely wrong?
 

Attachments

  • DB27198E-C9EF-4B93-89B3-77D1521C1A78.jpeg
    DB27198E-C9EF-4B93-89B3-77D1521C1A78.jpeg
    116.7 KB · Views: 526
Physics news on Phys.org
You see CMS during a maintenance phase where the detector was opened to access it. This typically happens every winter, with longer shutdowns (for 1-2 years) every few years.
During collisions it is closed.
 
  • Like
Likes YoungPhysicist
Thanks! I am correct for the first time! By the way, I got another question: when the maintenance is over, are the detector’s two halves brought together to seal the gap or an extra section is removed while mainiainance and installed back afterwards?(Since I didn’t see any sign of some sort of rail mechanism which makes the two halves moveable)
 
Thanks you so much!
 
Last edited:
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top