Coefficient of performance for a refrigerator

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SUMMARY

The coefficient of performance (COP) for refrigerators is calculated using the formula COP = T(low) / [T(high) - T(low)]. In this discussion, a refrigerator aiming for -10°C with an external temperature of 25°C yields a calculated COP of 7.5. However, this value exceeds the industry standard, which is approximately 50% of the Carnot limit. The discrepancy arises from misunderstanding the application of the Carnot COP in practical scenarios.

PREREQUISITES
  • Understanding of thermodynamics, specifically the Carnot cycle
  • Familiarity with the concept of coefficient of performance (COP)
  • Basic knowledge of temperature scales (Celsius)
  • Experience with heat pump and refrigeration principles
NEXT STEPS
  • Research the Carnot efficiency and its implications for real-world refrigeration systems
  • Study the factors affecting the COP of heat pumps and refrigerators
  • Learn about practical limitations of refrigeration cycles in industrial applications
  • Explore advanced thermodynamic equations related to refrigeration and heat pumps
USEFUL FOR

Students studying thermodynamics, engineers working in HVAC systems, and professionals involved in refrigeration technology.

rmjmu507
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Homework Statement



The COP for heat pumps and refrigerators achieved in the industry is almost 50% of the Carnot limit. Make estimates for the following case:

For refrigerator to achieve -10°C in the freezer area with an external temperature of 25°C

Homework Equations



COP for refrigerator = T(low) / [T(high)-T(low)]

The Attempt at a Solution



Using this equation, I find that the COP is 7.5, but this seems high. Where have I made a mistake?
 
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You calculated the Carnot COP but the problem statement says..

rmjmu507 said:
The COP for heat pumps and refrigerators achieved in the industry is almost 50% of the Carnot limit
 

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