Collecting gas over water with a eudiometer

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Discussion Overview

The discussion revolves around the collection of gas over water using a eudiometer, specifically addressing the calculation of total gas volume and pressure when switching between eudiometers during an experiment. The context includes a specific reaction involving butene gas and the implications of measuring displaced water volumes in different tubes.

Discussion Character

  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant questions whether the final volume of water displaced should be the sum of the volumes from both eudiometers or just the volume from the second tube.
  • Another participant suggests that only the final volume of water displaced in the second eudiometer should be considered.
  • A further inquiry is made regarding the reasoning for potentially ignoring the volume collected in the first tube, raising questions about the consistency of results when using different sized tubes.
  • There is a suggestion to consider whether the results would differ if the volume from the first tube is disregarded in a larger tube scenario.

Areas of Agreement / Disagreement

Participants express differing views on whether to combine the volumes from both eudiometers or to focus solely on the second tube's volume. The discussion remains unresolved, with multiple competing perspectives presented.

Contextual Notes

Participants have not reached a consensus on the assumptions regarding the measurement of gas volume and pressure when switching eudiometers, nor have they clarified the impact of tube size on the results.

elements
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Homework Statement


When, using a eudiometer in a lab to collect gas over water, if you have to switch eudiometers is the final volume of water displaced equal to the water displaced in the first tube + the water displaced in the second, and would the pressure be calculated through the total height displaced?

i.e.

Collecting butene gas from a reaction of BuBr and KOH in a 50mL eudiometer tube. The first tube all of the 50mL of H2O is displaced and the second tube 23mL is displaced.

Homework Equations


Total Volume = Volume displaced in first tube + Volume displaced in second
Pressure = Pressure of both heights combined

The Attempt at a Solution


Total Volume of gas produced = 50mL + 23mL=73mL of gas produced
Pressure = 50cm+(50-23cm)=770mmH2O
 
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elements said:
is the final volume of water displaced equal to the water displaced in the first tube + the water displaced in the second

And what is the alternative?
 
just the final volume of water displaced in the second eudiometer tube
 
So, what its the reasoning behind ignoring the first portion of gas collected?

Imagine using twice larger tube - should you get the same result, or a different one from the same experiment? Would you get the same result if you ignore the volume collected in the first tube?
 

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