Collecting gas over water with a eudiometer

Click For Summary
SUMMARY

The discussion centers on the use of a eudiometer to collect gas over water, specifically butene gas from a reaction between BuBr and KOH. When switching eudiometers, the total volume of gas collected is the sum of the volumes displaced in both tubes, resulting in a total of 73mL. The pressure is calculated by combining the heights of water displaced in both tubes, yielding a final pressure of 770mmH2O. Ignoring the volume collected in the first tube would lead to inaccurate results, as the total gas volume and pressure depend on both measurements.

PREREQUISITES
  • Understanding of gas collection techniques using eudiometers
  • Knowledge of gas laws and pressure calculations
  • Familiarity with the reaction between BuBr and KOH
  • Basic principles of water displacement in gas collection
NEXT STEPS
  • Research the principles of gas collection over water
  • Study the impact of varying eudiometer sizes on gas volume measurements
  • Learn about the calculation of pressure in gas collection experiments
  • Explore alternative methods for collecting gases in laboratory settings
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in gas collection experiments and those seeking to understand the principles of gas behavior in aqueous environments.

elements
Messages
29
Reaction score
0

Homework Statement


When, using a eudiometer in a lab to collect gas over water, if you have to switch eudiometers is the final volume of water displaced equal to the water displaced in the first tube + the water displaced in the second, and would the pressure be calculated through the total height displaced?

i.e.

Collecting butene gas from a reaction of BuBr and KOH in a 50mL eudiometer tube. The first tube all of the 50mL of H2O is displaced and the second tube 23mL is displaced.

Homework Equations


Total Volume = Volume displaced in first tube + Volume displaced in second
Pressure = Pressure of both heights combined

The Attempt at a Solution


Total Volume of gas produced = 50mL + 23mL=73mL of gas produced
Pressure = 50cm+(50-23cm)=770mmH2O
 
Physics news on Phys.org
elements said:
is the final volume of water displaced equal to the water displaced in the first tube + the water displaced in the second

And what is the alternative?
 
just the final volume of water displaced in the second eudiometer tube
 
So, what its the reasoning behind ignoring the first portion of gas collected?

Imagine using twice larger tube - should you get the same result, or a different one from the same experiment? Would you get the same result if you ignore the volume collected in the first tube?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 26 ·
Replies
26
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
10K
Replies
2
Views
2K
Replies
5
Views
4K
Replies
1
Views
3K