Collision between ball and stick

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SUMMARY

The discussion revolves around a physics problem involving a 0.58 kg glob of clay colliding with a 1.62 kg bar on a frictionless table. The clay strikes the bar perpendicularly at a distance of 0.18 m from the bar's center, resulting in a final center of mass speed of 1.63 m/s. Participants emphasize the use of conservation of angular momentum to determine the angular speed of the bar/clay system post-impact, noting that the initial angular momentum is zero due to the bar's lack of initial angular velocity.

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Homework Statement


On a frictionless table, a 0.58 kg glob of clay strikes a uniform 1.62 kg bar perpendicularly at a point 0.18 m from the center of the bar and sticks to it. If the bar is 0.70 m long and the clay is moving at 6.20 m/s before striking the bar, what is the final speed of the center of mass?
A=1.63m/s

At what angular speed does the bar/clay system rotate about its center of mass after the impact?
A=?

[PLAIN]http://img217.imageshack.us/img217/616/prob21a.gif


Homework Equations



Not sure

The Attempt at a Solution



I solved for the final speed of the center of mass using conservation of momentum, but i am lost on the 2nd part. I know the center of mass changes when the clay is attached to the bar, but I am not sure how i would use that to solve the question.
 
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Hi juggalomike! :wink:

Use conservation of angular momentum …

what do you get? :smile:
 
tiny-tim said:
Hi juggalomike! :wink:

Use conservation of angular momentum …

what do you get? :smile:

If i using conservation of angular momentum, which is Ii*Wi=If*Wf the initial side will be 0 because initialy it has no angular velocity?
 
Hello juggalomike,

Think about what is the center of mass of the system (the system being the combination of bar and glob) immediately before impact. Using that point as the center of mass, what is angular momentum (before impact) associated with the bar? And the glob? :wink:
 

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