- #1
blue5t1053
- 23
- 1
I'm unsure if I set this up correctly. It's a mulitple choice homework question and it doesn't match any possible answers.
Question:
A 0.605 kg ball drops vertically onto a floor, hitting with a speed of 34 m/s. It rebounds with an initial speed of 11 m/s. (a) What impulse acts on the ball during the contact? (b) If the ball is in contact with the floor for 0.0171 s, what is the magnitude of the average force on the floor from the ball?
Attempt:
Part A:
I = mvf - mvi
I = m(vf - vi)
I = 0.605(11-34)
I = -13.915 kg-m/sec
Attempt:
Part B:
If the contact time = 0.0171 s, then:
F = Δp/Δt = I/Δt = -13.915 kg-m/sec/0.0171 s
F = -813.743 Nt
Question:
A 0.605 kg ball drops vertically onto a floor, hitting with a speed of 34 m/s. It rebounds with an initial speed of 11 m/s. (a) What impulse acts on the ball during the contact? (b) If the ball is in contact with the floor for 0.0171 s, what is the magnitude of the average force on the floor from the ball?
Attempt:
Part A:
I = mvf - mvi
I = m(vf - vi)
I = 0.605(11-34)
I = -13.915 kg-m/sec
Attempt:
Part B:
If the contact time = 0.0171 s, then:
F = Δp/Δt = I/Δt = -13.915 kg-m/sec/0.0171 s
F = -813.743 Nt