Collision of Atoms: Find Motion & Speeds

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In an elastic collision, an atom of mass m collides with a stationary atom of mass 5m, resulting in the first atom moving in the y direction. The angle of motion for the second atom is calculated to be approximately 39.4° counterclockwise from the +x-axis. To find the speeds of both atoms after the collision, conservation of momentum principles should be applied, separating the momentum into x and y components. The initial calculations for the angle and one speed are correct, but further equations are needed to determine the second atom's speed. Visualizing the scenario with a diagram can aid in understanding the collision dynamics.
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An atom of mass m1 = m moving in the x direction with speed v1 = v collides elastically with an atom of mass m2 = 5m at rest. After the collision the first atom moves in the y direction. Find the direction of motion of the second atom. ________ ° counterclockwise from the +x-axis

Find the speeds of both atoms (in terms of v) after the collision.
v'1 = ________ v
v'2 = ________ v

The Attempt at a Solution


(a) arctan(5) = 78.7/2 = -39.4° counterclockwise from the +x-axis
(b) tan(39.4) = .821 v = v'2

I don't know what formulas/equations to use here and am unsure on how to get v'2. I have worked out the correct answers for (a) and the first part of (b).
 
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How about using the conservation of momentum to work it out? Split the momentum into individual components, in the x and y directions, and work from there. It also may help you visualize the situation if you draw the scenario out, both initial conditions, and final conditions.
 
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