Collision problem: Two hockey pucks collide and stick together....

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Two hockey pucks collide at a 90-degree angle and stick together, prompting a calculation of their post-collision speed and direction. The masses of the pucks are 0.71 kg and 0.52 kg, with initial speeds of 1.6 m/s and 3.8 m/s, respectively. The conservation of momentum equation is applied, but the initial solution was incorrect due to treating vector velocities as scalar speeds. The discussion emphasizes the need to consider the two-dimensional nature of the collision for accurate results. Understanding vector components is crucial for determining the correct speed and angle after the collision.
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Homework Statement


Two hockey pucks collide in a 90 degree angle and stick to each other. What's the speed of the hockey pucks after the collision and in what angle are the pucks moving in.

Homework Equations


m1=0.71kg
m2=0.52kg
v1=1.6m/s
v2=3.8m/s

The Attempt at a Solution


m1v1+m2v2=v(m1+m2)
=0.71kg*1.6m/s+0.52kg*3.8m/s=(0.71kg+0.52kg)*v
=v=(3.1kgm/s)/1.23kg=2.52m/s
 
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Hi Jeemeli and welcome to PF.

Is there something you wish to know about this? If so, please ask.
 
kuruman said:
Hi Jeemeli and welcome to PF.

Is there something you wish to know about this? If so, please ask.
My solution was wrong, Id like to know how to get the right answer
 
Jeemeli said:
m1v1+m2v2=v(m1+m2)
=0.71kg*1.6m/s+0.52kg*3.8m/s=(0.71kg+0.52kg)*v
You've gone from a correct formula involving vector velocities and applied it to scalar speeds.

If you walk 1.136 meters north and 1.976 meters east, how far from your starting position will you be as the crow flies?
 
Jeemeli said:
My solution was wrong, Id like to know how to get the right answer
In short, this is a two-dimensional collision.
 
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