Collisions problem (How should I approach it)

AI Thread Summary
The discussion revolves around solving a collision problem involving two blocks, focusing on the application of conservation of linear momentum and energy. The initial conditions indicate that only block A has kinetic energy before the collision, while post-collision, the kinetic energy of the system is halved. The user expresses confusion about handling three unknowns and whether to apply conservation principles correctly. A response clarifies the treatment of velocities, suggesting that the negative sign for block B's final velocity should be reconsidered to ensure all speeds are treated as positive. The conversation emphasizes the importance of setting up the equations accurately to solve for the unknowns effectively.
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Hi all,

I came across a problem on collisions on one of my professors old exams. The problem is:

http://home.comcast.net/~msharma15/problem_2.jpg

The way I am trying to approach it is by applying the conservation of linear momentum and energy, but the problem is that I still get left with 3 unknowns.

Here is what I know:
Before the collision, only block A has kinetic energy.

After the collision, the K.E. of system is (1/2 K.E. initial). block A has -1/2MV^2[/color] and block B has 1/2MV^2[/color].

The final collision is what confuses me. Should I just work with K.E.i (only block A moving) with conservation of linear momentum?

Any help would be greatly appreciated. Thanks!
 
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by cons of p,
m_1v_{1i}=m_1v_{1f}-m_2v_{2f}
where v_2f is reckoned as negative
By the energy conditions,
m_1v_{1i}^2=\frac {1}{2}(m_1v_{1f}^2+m_2v_{2f}^2)
which gives two equations with two unknowns.
 
Thanks for the reply
StephenPrivitera. I am just wondering why you made m_2v_2f negative in the first equation?? Should it be the other way around?
 
The equations should be:
m_1v_{1i}=-m_1v_{1f}+m_2v_{2f}
\frac {1}{4}m_1v_{1i}^2=\frac {1}{2}(m_1v_{1f}^2+m_2v_{2f}^2)
(where the speeds are all positive)
 
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