Collisions/Projectile Motion (AP Free-response)

  • Thread starter Thread starter TheFireFox
  • Start date Start date
  • Tags Tags
    Motion
AI Thread Summary
The discussion focuses on a physics problem involving a bullet colliding with a block on a frictionless table and the subsequent motion after the impact. For part A, the speed of the block after the collision is derived using conservation of momentum, resulting in Vf = Vo/101. In part B, the change in kinetic energy is calculated as Delta KE = KEf - KEi, where KEf involves the combined mass of the bullet and block. Part C's horizontal distance x is clarified to depend on the final velocity and time, with time calculated from vertical motion equations. Parts D and E explore the independence of fall time from horizontal velocity and the energy transfer implications based on whether the bullet passes through the block.
TheFireFox
Messages
2
Reaction score
0

Homework Statement



3. A bullet of mass m is moving horizontally with speed vowhen it hits a block with mass 100m that is at rest on a horizontal frictionless table. The surface of the table is height h above the floor. After the impact the bullet and the block slide off the table and hit the floor at a distance x from the edge of the table.

Derive expressions in terms of m, h, Vo, and constants.

A. The speed of the block as it leaves the table
B. Delta KE of the system during impact
C. The horizontal distance X.
If the bullet passes through:
D. Is the time to reach the floor greater, smaller or equal/ Why?
E. Is the distance x smaller, greater equal/ Why?

Homework Equations



I'm assuming that conservation of momentum has something to do with part A; Delta KE= KEf- KEri, and KE= (0.5)mv2 for part B, General kinematics equations for Part C (I'm guessing D= Vit+0.5at2) , and I'm confused about D and E.

The Attempt at a Solution



A. mVo=(m+100m)Vf
Vf=(mVo) / (m+100m) = mVo / m(1+100) = Vo/101

B. Delta KE = KEf-KEi

=0.5(1+100m)Vf2 - 0.5 mVo2

C. x=Vi + 0.5at2


I'd greatly appreciate any help/feedback.
 
Physics news on Phys.org
Your approaches to parts A and B are correct. Part C is not correct because there is no accelerating force in the horizontal, x, direction. So x = Vft. The time, t, is found from h = 1/2gt2 since Vo = 0 (no initial velocity in the vertical or y direction). As for parts D and E, consider if the amount of time for the block to hit the floor is independent or dependent on the initial horizontal velocity, and consider the amount of energy delivered to the block by the bullet if the bullet passed through compared to the bullet remaining in the block and how this would affect the horizontal initial velocity of the block.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top