How Do You Solve a Combination Lens Problem in Optics?

  • Thread starter Thread starter Darth Frodo
  • Start date Start date
  • Tags Tags
    Combination Lens
AI Thread Summary
An object is placed 400 mm in front of a convex lens with a focal length of 80 mm, resulting in an image formed 100 mm to the right of the first lens. A second concave lens, positioned 80 mm behind the convex lens, requires the image from the first lens to act as the object for the second. The object distance for the concave lens is calculated as -20 mm, leading to the final image position being determined. The final image is found to be 100 mm from the concave lens, indicating it is virtual and located on the same side as the object.
Darth Frodo
Messages
211
Reaction score
1

Homework Statement



An object is placed 400 mm in front of a convex lens of focal length 80 mm. Find the position of the image formed. State the nature of this image.

A second concave lens of focal length 25 mm is placed 80 mm behind the first convex lens. Find the position of the final image formed and state its nature.

The Attempt at a Solution



\frac{1}{U} + \frac{1}{V} = \frac{1}{F}

\frac{1}{V} = \frac{1}{80} - \frac{1}{400}

V = 100 mm



So the Image from lens one forms 100 mm to the right of lens one. BUT, lens 2 is only 80 mm to the right of lens 1. I don't know what to do here since no image has been formed to create a new object for lens 2.

Any help?
 
Physics news on Phys.org
Which means the Object´s image will appear to the right (or behind) of the concave lense.
80-100= -20
U=-20 solve for V
 
\frac{1}{-20} + \frac{1}{V_{2}} = \frac{1}{F}

\frac{1}{V_{2}} = \frac{1}{20} - \frac{1}{25} = \frac{1}{100}

V = 100
 
Is this correct?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top