How Do You Solve a Combination Lens Problem in Optics?

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An object is placed 400 mm in front of a convex lens with a focal length of 80 mm, resulting in an image formed 100 mm to the right of the first lens. A second concave lens, positioned 80 mm behind the convex lens, requires the image from the first lens to act as the object for the second. The object distance for the concave lens is calculated as -20 mm, leading to the final image position being determined. The final image is found to be 100 mm from the concave lens, indicating it is virtual and located on the same side as the object.
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Homework Statement



An object is placed 400 mm in front of a convex lens of focal length 80 mm. Find the position of the image formed. State the nature of this image.

A second concave lens of focal length 25 mm is placed 80 mm behind the first convex lens. Find the position of the final image formed and state its nature.

The Attempt at a Solution



\frac{1}{U} + \frac{1}{V} = \frac{1}{F}

\frac{1}{V} = \frac{1}{80} - \frac{1}{400}

V = 100 mm



So the Image from lens one forms 100 mm to the right of lens one. BUT, lens 2 is only 80 mm to the right of lens 1. I don't know what to do here since no image has been formed to create a new object for lens 2.

Any help?
 
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Which means the Object´s image will appear to the right (or behind) of the concave lense.
80-100= -20
U=-20 solve for V
 
\frac{1}{-20} + \frac{1}{V_{2}} = \frac{1}{F}

\frac{1}{V_{2}} = \frac{1}{20} - \frac{1}{25} = \frac{1}{100}

V = 100
 
Is this correct?
 
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