Combinations Problem: Solving k Value in Homework Equation

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The discussion focuses on solving for the k value in a combinatorial equation related to a homework problem. The equation involves expanding (x^2 + 1/x)^{10} and finding the coefficient of x^11. The user attempts to derive k by setting up the equation 3k - 10 = 11, aiming to identify the correct k value. There is confusion regarding the placement of the terms in the expansion, particularly whether the 1 or x^3 should be associated with the y value. Ultimately, the user questions the validity of k being equal to 3 in their calculations.
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Homework Statement


http://img234.imageshack.us/img234/8519/combgf7.png​
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Homework Equations


{t}_k_+_1=_n{C}_kx^n^-^ky^k


The Attempt at a Solution


The picture I have shown contains the problem and the teacher's solution. However, I was wondering how the k value is 3. And no, I can't ask the teacher; my test is tomorrow.
 
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This is how I would do it

(x^2+\frac{1}{x})^{10}=[\frac{1}{x}(x^3+<br /> 1)]^{10}

=\frac{1}{x^{10}}(x^3+1)^{10}

and you want the coefficient of x^11

so if you expand you will get

=\frac{1}{x^{10}}(...+^{10}C_k(1)^{10-k}(x^3)^k+...)

You need to find k and you want the power of x to be 11

so that 3k-10=11

See it?
 
rock.freak667 said:
=\frac{1}{x^{10}}(...+^{10}C_k(1)^{10-k}(x^3)^k+...)

You need to find k and you want the power of x to be 11

so that 3k-10=11

For your expansion, isn't the 1 supposed to be where the x^3 is? Because 1 is the y value, while x^3 is the x value.

Also, k doesn't equal 3 in 3k-10=11
 
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