Common source amplifier low frequency resonse

[TheRedDevil18]

Here's the amplifier in question:

I'm not understanding this part:

Why is Cs not included in the current divider ?
To my understanding of current divider, It = Id+Io, where It is the current flowing through Rd
So, Io = It*(1/Cs)/(1/Cc2)+RL

 

[Jony130]

But Cs is in series with Id current. Please explain to me how Cs affects Io.

 

[TheRedDevil18]

But Cs is in series with Id current. Please explain to me how Cs affects Io.

Yes, it's correct. I must have gotten confused somewhere but it's fine now

 

[Jony130]

Do you have any more qestion about this amp?

 

[TheRedDevil18]

Do you have any more qestion about this amp?
View attachment 104139

No, I'm good, thanks