Comparing Resistance in PN Diodes

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In the discussion about resistance in PN diodes, it is established that when the diode is forward-biased (as in circuit A), the resistance is low, allowing current to flow. Conversely, in circuit C, where the diode is reverse-biased, the resistance is high, resulting in minimal current. Circuit B is identified as a p-type semiconductor, with its resistance influenced by doping levels and temperature. The analysis confirms that the reverse-biased diode offers the highest resistance, provided the voltage remains below the breakdown threshold. Understanding these principles is crucial for evaluating diode behavior in circuits.
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Homework Statement


I came across a question asking " which one of these circuits has the largest resistance to the current?
h762y.jpg


Homework Equations

The Attempt at a Solution


* In A the positive terminal of the battery is connected to the p-type region and the negative one to the n-type region (forward bias) so, the field due to the battery is opposite to the internal field in the transition region and therefore, it weakens it. The resistence will be small and the current will flow.
* C is the opposite case of A since it shows that the pn diode is connected in reverse direction. The resistance will be large and the current is almost zero.
But I'm not sure about the B case.
 

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Eman 55 said:

Homework Statement


I came across a question asking " which one of these circuits has the largest resistance to the current?
View attachment 227031

Homework Equations

The Attempt at a Solution


* In A the positive terminal of the battery is connected to the p-type region and the negative one to the n-type region (forward bias) so, the field due to the battery is opposite to the internal field in the transition region and therefore, it weakens it. The resistence will be small and the current will flow.
* C is the opposite case of A since it shows that the pn diode is connected in reverse direction. The resistance will be large and the current is almost zero.
But I'm not sure about the B case.
B is a "resistor " with positive charge carriers. It can be a piece of p-type semiconductor.
 
Eman 55 said:

Homework Statement


I came across a question asking " which one of these circuits has the largest resistance to the current?
View attachment 227031

Homework Equations

The Attempt at a Solution


* In A the positive terminal of the battery is connected to the p-type region and the negative one to the n-type region (forward bias) so, the field due to the battery is opposite to the internal field in the transition region and therefore, it weakens it. The resistence will be small and the current will flow.
* C is the opposite case of A since it shows that the pn diode is connected in reverse direction. The resistance will be large and the current is almost zero.
But I'm not sure about the B case.
You are right in your analysis. The diode in figure C is reverse-biased and will offer the largest resistance to the current (assuming that the applied voltage is low enough to prevent reverse-breakdown).
Figure B shows a p-type semiconductor. Its conductivity will depend on the amount of doping and temperature.
 
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