Comparing Speeds of Golf Ball and Ping Pong Ball with Equal Kinetic Energy

  • Thread starter Thread starter fattydq
  • Start date Start date
  • Tags Tags
    Ball Golf
AI Thread Summary
When comparing a golf ball and a Ping-Pong ball with equal kinetic energy, the relationship defined by kinetic energy (KE = 1/2 M*V^2) indicates that the ball with greater mass must have a lower speed. Since the golf ball is significantly heavier than the Ping-Pong ball, it must travel slower to maintain the same kinetic energy. This conclusion is based on the inverse relationship between mass and velocity in the kinetic energy formula. The discussion confirms that the golf ball, having more mass, indeed moves at a slower speed than the Ping-Pong ball when both possess equal kinetic energy. Understanding this principle clarifies the dynamics of mass and speed in physics.
fattydq
Messages
79
Reaction score
0
If a golf ball and a Ping-Pong ball both move with the same kinetic energy, can you say which has the greater speed? Explain in terms of the definition of kinetic energy.

Can you guys tell me if I'm thinking along the correct lines in my response...

Kinetic energy = 1/2 M*V^2.
Since the golf ball has a higher mass than the pingpong ball, the only way they could both have the same kinetic energy is if the golf ball has a slower speed.
 
Physics news on Phys.org
Correct!
 
ill said:
Correct!

K, thanks...haha I'll try to keep these questions to a minimum when they're so simple but it was so simple I felt like I was overlooking something haha
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Golf club 🏌️and ball ⛳ impulse problem
Replies
19
Views
2K
Ball on a string thrown around a spool
Replies
3
Views
835
Calculating Force Applied to Golf Ball by Club with Limited Data
Replies
6
Views
7K
A ball climbing a ramp while "rolling the wrong way"
Replies
32
Views
3K
Kinetic Energy & Momentum of a Ball released from Spring
Replies
6
Views
2K
Question about the Kinetic Energy of a baseball in flight
Replies
8
Views
3K
How to calculate rebound speed of ball hitting a wall?
Replies
4
Views
5K
Bernoulli's Equation with a ping pong ball
Replies
1
Views
4K
Ping-Pong Ball Submerged in Water and then Released
Replies
12
Views
8K
Calculation to launch a golf ball
Replies
5
Views
1K

Hot Threads

Recent Insights

Back
Top