1. The problem statement, all variables and given/known data In Fig. 9-64, block 2 (mass 1.0 kg) is at rest on a frictionless surface and touch- ing the end of an unstretched spring of spring constant 200 N/m. The other end of the spring is fixed to a wall. Block 1 (mass 2.0 kg), traveling at speed v1 = 4.0 m/s, collides with block 2, and the two blocks stick together. When the blocks momentarily stop, by what distance is the spring compressed? 2. Relevant equations m1v1+m2v2=MV where M is the mass of the system and V is the velocity of the system Hooke's Law: F = kx 3. The attempt at a solution I was able to find the final velocity of the system: V = (m1v1)/(m1+m2) = 2.974 How do I get from there to the distance that the spring is compressed?