Completeness axiom/theorem and supremum

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Homework Help Overview

The discussion revolves around proving a statement related to the completeness axiom and supremum of products of bounded non-empty sets of real numbers. The original poster presents a mathematical problem involving sets A and B, and their product set C.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to establish that the product of the suprema serves as an upper bound for the set C. There are attempts to manipulate inequalities involving the suprema and elements of the sets. Questions arise about the nature of the sets A and B, particularly regarding whether they contain strictly positive numbers.

Discussion Status

Participants are exploring various approaches to demonstrate the properties of the supremum in this context. Some guidance has been offered regarding the steps needed to show that the product of the suprema is an upper bound and to establish it as the least upper bound. There is an ongoing examination of assumptions about the sets involved.

Contextual Notes

There is a noted ambiguity regarding whether the sets A and B consist of strictly positive numbers, which has led to some confusion and debate among participants. This uncertainty may impact the validity of the proposition being discussed.

Treadstone 71
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"Let A and B be bounded nontempty sets of real numbers. Let C={ab:a in A, b in B}. Prove that sup(C)=sup(A)sup(B)."

Here's what I've done so far:

By the completeness axiom/theorem A and B have suprema. Let sup(A)=z and sup(B)=y. For all e>0, there exists a in A and b in B such that z-e<a and y-e<b. Multiplying the two inequalities and we have

zy-ze-ye+e^2 < ab

I'm stuck here.
 
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Treadstone 71 said:
"Let A and B be bounded nontempty sets of real numbers. Let C={ab:a in A, b in B}. Prove that sup(C)=sup(A)sup(B)."
Here's what I've done so far:
By the completeness axiom/theorem A and B have suprema. Let sup(A)=z and sup(B)=y. For all e>0, there exists a in A and b in B such that z-e<a and y-e<b. Multiplying the two inequalities and we have
zy-ze-ye+e^2 < ab
I'm stuck here.

It would be a good idea to show first that zy is an upper bound on C!
You are using the fact that since z is the least upper bound on A there must be an a between z-e and z and since y is the least upper bound on B there must be a b between z-e and z. What does that tell you about there being an ab between zy- e and z?
 
step 1 show it's an upper bound,

step 2 show it is a least upper bound which can be messy.

it's easier to use the definition of sup as the maximum of the accumulation points.

You need to show that give d>0 you can find e greater than zero such that 0<ey+ez-e^2<d, so do that.
 
I don't know, but I want to arrive at the conclusion that zy-x<ab for all x>0. If I could prove that zy-(?)<ab where (?) is positive, then I'm done, since I can let x=(?).
 
we may suppose e<z and e<y, can you see how that might help?
 
e>0. z and y could be negative.
 
How can the supremum of a set of positive numbers be negative?
 
A and B aren't sets of strictly positive numbers.
 
Then the proposition is trivially false.
 
  • #10
You're right. This is odd considering it's an archived analysis final exam.
 
  • #11
The odd thing is that at one point i even checked back to make sure that these were sets of positive numbers just so i didn't make a mistake and i am convinced that i remember reading that you wrote they were positive real numbers. Odd.
 

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