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This isn't really homework help. I'm working through a complex analysis textbook myself, and am stumped on the complex transcendentals, but I figured this was the best place for it. I would greatly appreciate any guidance here, I'm getting very frustrated!
The problem is to find all solutions of [itex]e^{2iz} = 1[/itex] where [itex] z \in \mathbb{C}[/itex].
The correct answer is, I believe [itex]z = n \pi[/itex] for any integer n.
Euler's equation: [itex]-1 = e^{i \pi}[/itex]
I tried turning the right hand side into [itex]-e^{i \pi}[/itex] via Euler's equation, then taking a logarithm of both sides... gives [itex] 2iz = i \pi[/itex]... but Wolfram Alpha says the answer is [itex]n \pi[/itex] where [itex] n \in Z[/itex]. Clearly not where I got to.
Homework Statement
The problem is to find all solutions of [itex]e^{2iz} = 1[/itex] where [itex] z \in \mathbb{C}[/itex].
The correct answer is, I believe [itex]z = n \pi[/itex] for any integer n.
Homework Equations
Euler's equation: [itex]-1 = e^{i \pi}[/itex]
The Attempt at a Solution
I tried turning the right hand side into [itex]-e^{i \pi}[/itex] via Euler's equation, then taking a logarithm of both sides... gives [itex] 2iz = i \pi[/itex]... but Wolfram Alpha says the answer is [itex]n \pi[/itex] where [itex] n \in Z[/itex]. Clearly not where I got to.