Complex Integrals - Poles of Integration Outside the Curve

SirFibonacci
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Homework Statement



\int_{|z-2i|=2} = \frac{dz}{z^2-9}



2. The attempt at a solution

I know that the contour described by |z-2i|=2 is a circle with a center of (0,2) (on the complex plane) with a radius of 2. The singularities of the integral fall outside of the contour (z+3 and z-3). In this case, is the solution just going to be zero or undefined?
 
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Your integrand is analytic in a region that contains your contour, what do you know about a closed contour integral of an analytic function?
 
The integral is 0. Makes sense. Thanks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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