Complex Integration Homework - Part (a) and (b) Help

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Homework Statement



attachment.php?attachmentid=68696&stc=1&d=1397618882.jpg


Homework Equations





The Attempt at a Solution



I did part (a) which is pretty easy. Use the Cauchy integral formula. Part (b) says "hence", which leads me to believe that part (a) can be used for part (b), but I cannot see anything remotely related between the two. I don't want to do weird manipulations and substitutions if part (a) can help.

If someone could help me out with this I would really appreciate it.
 

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stripes said:

Homework Statement



attachment.php?attachmentid=68696&stc=1&d=1397618882.jpg


Homework Equations





The Attempt at a Solution



I did part (a) which is pretty easy. Use the Cauchy integral formula. Part (b) says "hence", which leads me to believe that part (a) can be used for part (b), but I cannot see anything remotely related between the two. I don't want to do weird manipulations and substitutions if part (a) can help.

If someone could help me out with this I would really appreciate it.

Just substitute ##e^{i \theta}## for ##z## in the integral and turn it into an integral ##d\theta##. Then use deMoivre.
 
Thanks Dick! Easy as pie now
 
Here is an elementary approach for part b) if you like:

Notice that the integral you seek is
$$\begin{aligned}
\Re\left(\int_0^{\pi} e^{k\cos t}e^{ik\sin t}\,dt\right) &= \Re\left(\int_0^{\pi}e^{ke^{it}}\,dt\right)\\
&=\Re\left(\int_0^{\pi} \left(1+ke^{it}+k^2e^{2it}+\cdots \right)\,dt\right)\\
&=\boxed{\pi}\\
\end{aligned}$$
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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