Complex-Phasor (Moved from physics)

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Two alternating currents of 4 volts and 3 volts at 27° out of phase are analyzed through phasor representation. The user attempts to draw both phasors and calculate the combined phasor's peak voltage, arriving at a value of 6.81 volts. Clarification is sought on whether the drawn images accurately represent the phasors and if the peak voltage should be labeled on the graph. Responses indicate that the combined phasor needs to be illustrated as a separate entity and suggest using the parallelogram rule for clarity. The discussion emphasizes the importance of correctly visualizing and labeling phasors in the context of alternating currents.
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Homework Statement



Two alternating currents are applied out of phase with each other. One is 4 volts and the other is 3 volts 27° out of phase.

These can be written as (4, 0°) and (3, 27°)


Homework Equations



a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value



The Attempt at a Solution



a)A rough drawing on paint http://imageshack.us/photo/my-images/3/plotb.jpg/

b) I know A= 6.8106 volts by using this formula

r=√a2+b2

r=3cos27 + 4i + i(3sin 27)

r=√(3cos27 + 9)2 + (3sin27)2

=6.81v

angle=0.2014


Image 2 attached.


Please look at both images, which are correct
 

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maali5 said:

Homework Statement



Two alternating currents are applied out of phase with each other. One is 4 volts and the other is 3 volts 27° out of phase.

These can be written as (4, 0°) and (3, 27°)

Homework Equations



a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value

The Attempt at a Solution



a)A rough drawing on paint http://imageshack.us/photo/my-images/3/plotb.jpg/

b) I know A= 6.8106 volts by using this formula

r=√a2+b2

r=3cos27 + 4i + i(3sin 27)

r=√(3cos27 + 9)2 + (3sin27)2

=6.81v

angle=0.2014Image 2 attached.Please look at both images, which are correct

Is there a question here?
 
LCKurtz said:
Is there a question here?

Yeh

(4,0°) and (3,27°)

a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value
 
LCKurtz said:
Is there a question here?

maali5 said:
Yeh

(4,0°) and (3,27°)

a)draw both phasors
b)draw the combined phasor between (0 degree and 360 degree)
c)label peak voltage and state its value

Well, yes, those are the questions you are working on. I knew that. And I see you have worked on them. What is your question that you are seeking help on here?
 
I have drawn two images. Also done a calculation.

I was wondering if the images and calculation are correct?
 
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number.
 
LCKurtz said:
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number.

b)How should I draw a phasor?

c) Again any help on what number ?
 
try sketching both graphs on the same axis... then imagine what the sum might look like.
 
maali5 said:
b)How should I draw a phasor?
The same way you drew phasors for part (a).
c) Again any help on what number ?

You already calculated it, didn't you?
 
  • #10
LCKurtz You have confused me.

Let's rewind back- I have drawn two images

i) (http://imageshack.us/photo/my-images/3/plotb.jpg

ii) The attached image



Then you said

"
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number."



My reply to you question:

For the phasor image would that not be image (i) and for c the number (=6.81v ).

And last but not least should I label (6.81v) on graph B.


Thanks again
 
  • #11
maali5 said:
LCKurtz You have confused me.

Let's rewind back- I have drawn two images

i) (http://imageshack.us/photo/my-images/3/plotb.jpg

ii) The attached image



Then you said

"
Your work looks OK, but I think your answer to (b) should be a picture of a phasor (which I don't see anywhere) and your answer to (c) should just be a number."



My reply to you question:

For the phasor image would that not be image (i)

Part (a) Said draw both phasors. That's apparently what you did in image 1, although I would put a little arrowhead on the tips of both.

and for c the number (=6.81v ).

And last but not least should I label (6.81v) on graph B.

Thanks again

Part (b) asks for the "combined phasor". That is another phasor like in part (a). It is just the result of adding the two given phasors and would be easy to include in your image 1. But when it asks for the combined phasor "between 0 and 360" maybe it means the corresponding sine wave like in your other image. Either way the 6.81 is the amplitude of the sine wave you have drawn and is also the length of the combined phasor, which you have not drawn yet.
 
  • #12
Thank you!

One last question for the combined phasor. How should I be able to draw that?

Would you please be able to attach simple exam on how to draw one? As I do not where to start.
 
  • #13
maali5 said:
Thank you!

One last question for the combined phasor. How should I be able to draw that?

Would you please be able to attach simple exam on how to draw one? As I do not where to start.

You calculated its length and angle (in radians) in your first post. Just draw it like you did the others. Or you could geometrically use the parallelogram rule for adding the two vectors (phasors) in your first picture. Or if it's the sine wave they want, you have already drawn it.
 
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