Composition of trigonometric functions, mean value theorem

zbot1
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Homework Statement



how to show using MVT that cos(cos x) is a contraction.

Homework Equations



| d/dx (cos(cos x)) | = | sin(cos x) sin(x) | < sin 1 < 1

The Attempt at a Solution



Using that relation, the original problem is easily solved. My question is, how do we know:

| sin(cos x) sin(x) | < sin 1 ?

-zbot1
 
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zbot1 said:

Homework Statement



how to show using MVT that cos(cos x) is a contraction.

Homework Equations



| d/dx (cos(cos x)) | = | sin(cos x) sin(x) | < sin 1 < 1

The Attempt at a Solution



Using that relation, the original problem is easily solved. My question is, how do we know:

| sin(cos x) sin(x) | < sin 1 ?

-zbot1

-1<=cos(x)<=1. What does that make the range of values for sin(cos(x))?
 
Thanks!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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