How to Find the Exact Values of Cosine and Sine of Compound Angles

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To find the exact values of cosine and sine for the angles x and y, given sin x = 3/5 and cos y = 5/13, one can use the Pythagorean identity sin²x + cos²x = 1 to derive cos x and sin y. For cos x, calculate √(1 - (3/5)²), resulting in cos x = 4/5. For sin y, calculate √(1 - (5/13)²), leading to sin y = 12/13. The discussion highlights the importance of using trigonometric identities to solve for unknown values in compound angles. Understanding these relationships is crucial for solving similar problems in trigonometry.
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Homework Statement



Angles x and y are located in the first quadrant such that sin x = 3/5 and cos y = 5/13.

a) Determine the exact value for cosx
b) Determine the exact value for siny


Homework Equations





The Attempt at a Solution



I don't know what to do.
Am I supposed to do something with the angle a+b?
 
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Use the expression sin2x + cos2x = 1, x being either alpha or beta :) .
 
oh jeez i feel dumb
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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