Understanding the Work Required to Compress Water Vapor at 200 atm

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The exercise involves compressing water vapor to 99% of its volume at a pressure of 200 atm, raising questions about the process's nature. Clarification is needed on whether the compression occurs quasistatically from atmospheric pressure to 200 atm and whether it is isothermal or adiabatic. The ambiguity in the problem statement leads to confusion regarding the application of pressure and the assumptions necessary for calculations. Understanding the process type is crucial for accurately estimating the work required for this compression. The lack of specific details in the exercise prompts further discussion on the correct approach to solving it.
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Okay my exercise says the following:

"By applying a pressure of 200 atm, you can compress water to 99% of its usual volume. Find the work needed to do this."

Now I'm having a bit of trouble with how this is put. For me it doesn't make sense to just put 200atm pressure on normal pressured water vapour. Don't they mean between the lines, that the water has been slowly pressured quasistatically from normal pressure to 200atm pressure?
 
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we need to know whether this is done isothermally or adiabatically
 
The exact text is: "By applying a pressure of 200atm you can compress water to 99% of its usual volume. Sketch this proces (not neccesarily to scale) on a PV diagram, and estimate the work required to compress a liter of water by this amount. Does the result surprise you?"

Now I just want to know if you are to assume that the water is compressed slowly beggining from atmospheric pressure until 200 atm? It doesn't really make sense to just apply 200atm, or am I reading it wrong? Now you are also right that information lacks about it being adiabatic or isothermal..
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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