Compressor work and Thermodynamics

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The discussion focuses on evaluating compressor work using Cp.dT, even when inlet and outlet pressures differ. While Cp is typically associated with constant pressure processes, for ideal gases, the enthalpy change ΔH remains equal to CpΔT regardless of pressure variations. This is due to the definition of Cp in thermodynamics, which relates to enthalpy rather than heat transfer. When considering varying heat capacities, the enthalpy change can be accurately calculated by integrating dH = Cp dT between the initial and final temperatures. Understanding these principles is crucial for accurate thermodynamic analysis in compressor work scenarios.
rishi kush
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how can we use Cp.dT to evaluate compressor work even when one side (inlet side) is having different pressure than other side (outlet side). Cp should be used for constant pressure!
 
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rishi kush said:
how can we use Cp.dT to evaluate compressor work even when one side (inlet side) is having different pressure than other side (outlet side). Cp should be used for constant pressure!
For a constant pressure process, the amount of heat Q is equal to ##C_p\Delta T##. Otherwise, Q is not equal to that. But, for an ideal gas, irrespective of the pressure variation, the enthalpy change ##\Delta H## is always equal to ##C_p\Delta T##. This is because, in thermodynamics, ##C_p## is defined in terms of the enthalpy change rather than in terms of the amount of heat transferred. The two definitions match only if the pressure is constant.
 
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since Cp is a state function , its value should be different for initial and final states of a process? and which value should we have to consider?
 
rishi kush said:
since Cp is a state function , its value should be different for initial and final states of a process? and which value should we have to consider?
If you have a heat capacity which varies with temperature, you integrate ##dH=C_pdT## between the initial and final temperatures to get the enthalpy change.
 
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