- #1
Khasimir
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Hallo
I don't understand why I can't use
Δλ = λ'- λ = h/(m·c) · ( 1 - cos φ )
and ΔE = h · c / Δλ
for getting the energy ΔE which is transferred to the electron
In school we did it like this: 1/f'- 1/f = h/(m·c) · ( 1 - cos φ )
<-> E' = hf' = hf/(1 + hf(1 - cos φ )/(mc^2))
-> ΔE = E (energy of photon before scattering) - E' (energy of photon after)
I really need help
Christoph
I don't understand why I can't use
Δλ = λ'- λ = h/(m·c) · ( 1 - cos φ )
and ΔE = h · c / Δλ
for getting the energy ΔE which is transferred to the electron
In school we did it like this: 1/f'- 1/f = h/(m·c) · ( 1 - cos φ )
<-> E' = hf' = hf/(1 + hf(1 - cos φ )/(mc^2))
-> ΔE = E (energy of photon before scattering) - E' (energy of photon after)
I really need help
Christoph