Concavity of Parametric Equations

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SUMMARY

The discussion centers on finding the second derivative of parametric equations to determine concavity. The equations provided are x = e^t and y = te^(-t), leading to the second derivative d^2y/dx^2 = e^(-3t)(2t - 3). The user initially concluded that concavity is upward for t > 3/2, but this was incorrect. The confusion arose from the incorrect application of the exponential function in the context of the cosine-based parametric equations x = cos(2t) and y = cos(t), which were later introduced.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of derivatives and second derivatives
  • Familiarity with concavity and its determination
  • Ability to solve inequalities
NEXT STEPS
  • Learn how to compute derivatives of parametric equations
  • Study the concept of concavity in calculus
  • Explore the relationship between second derivatives and concavity
  • Practice solving inequalities related to concavity
USEFUL FOR

Students studying calculus, particularly those focusing on parametric equations and concavity analysis, as well as educators seeking to clarify these concepts in instructional settings.

sheldonrocks97
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Homework Statement



Find dy/dx and d^y/dx^2

x=e^t; y=te^(-t)

For which values of t are concave upward? (write your answer in interval notation).

Homework Equations


The Attempt at a Solution



I used the formula to find d^2y/dx^2.

d^2y/dx^2= e^(-3t)*(2t-3)

Set it to zero:

e^(3t)*(2t-3)>0

I solved it and got t>3/2, but the computer told me it was wrong. What am I doing wrong here?
 
Last edited:
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sheldonrocks97 said:

Homework Statement



Find dy/dx and d^y/dx^2

x = cos 2t, y = cos t, 0 < t < ∏

For which values of t are concave upward? (write your answer in interval notation).

Homework Equations





The Attempt at a Solution



I used the formula to find d^2y/dx^2.

d^2y/dx^2= e^(-3t)*(2t-3)

I solved it and got t>3/2, but the computer told me it was wrong. What am I doing wrong here?

Where did the exponential come from? You only have cosines in the problem. After you fix that, please show your work so we can follow it.
 
LCKurtz said:
Where did the exponential come from?
The OP edited his post, so the parametric equations now have exponential form
LCKurtz said:
After you fix that, please show your work so we can follow it.
Yes. Show your work for dx/dt and dy/dt and so on.
 

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