Conceptual question concerning functions

Duderonimous
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Homework Statement



If I have a function that is not defined at a point in its domain is this the same as saying it is discontinuous?

Homework Equations





The Attempt at a Solution

 
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Duderonimous said:

Homework Statement



If I have a function that is not defined at a point in its domain is this the same as saying it is discontinuous?

Homework Equations


The Attempt at a Solution


If it's not defined at some point, then that point is not in the domain of that function.

If the function is not defined at some point, then it is discontinuous at that point.
 
Duderonimous said:
If I have a function that is not defined at a point in its domain is this the same as saying it is discontinuous?

No. If a function is not defined at a point, then that point is not in its domain. But a function can be continuous at each point of its domain notwithstanding that its domain consists of disjoint subsets of some larger set. For example, the following function is continuous everywhere in its domain:
<br /> f : \mathbb{R} \setminus \{0\} \to \mathbb{R} : x \mapsto \left\{\begin{array}{r@{\qquad}l}<br /> 0 &amp; x &lt; 0 \\<br /> 1 &amp; x &gt; 0<br /> \end{array}\right.<br />
On the other hand, there is no a \in \mathbb{R} such that the following function is continuous at 0:
<br /> g : \mathbb{R} \to \mathbb{R} : x \mapsto \left\{\begin{array}{r@{\qquad}l}<br /> f(x) &amp; x \neq 0 \\<br /> a &amp; x = 0<br /> \end{array}\right.<br />
 
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