Confirm correctness of simple Newton's second law-type problem?

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Homework Help Overview

The problem involves a 4 kg mass subjected to two forces, F1 and F2, with the goal of determining the object's velocity at a specific time, the time it stops moving in the j direction, and its displacement at another time. The context is rooted in Newton's second law and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss separating the velocity and acceleration components in the i and j directions. There are attempts to apply kinematic equations and Newton's second law to find the required values. Questions arise regarding the integration of acceleration and the correct application of kinematic principles.

Discussion Status

Some participants have suggested finding velocity and acceleration separately for each direction. There is ongoing exploration of how to integrate acceleration and apply kinematic equations, with no clear consensus on the approach to take for the displacement calculation.

Contextual Notes

Participants are navigating the complexities of integrating forces and acceleration over time, with some uncertainty about the correct methods and assumptions involved in the problem setup.

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Homework Statement


at t=0, a 4kg mass is moving at 2 m/s\hat{i} + 3m/s\hat{j}
at t=0, F1 and F2 act upon the object
F1= [1 N + (1/2 N/s)t ]\hat{i}
F2= -(1/3 N/s2)t2 \hat{j}

a) what is the object's velocity when t=3?
b) at what time does the object stop moving in \hat{j} direction?
c) what is the object's displacement when t=6?

Homework Equations


F=ma
kinematics

The Attempt at a Solution


just look at the steps and see if I'm doing it right please

\vec{V}0 = 2 m/s\hat{i} + 3m/s\hat{j}
\vec{F}(t) = [1 N + (1/2 N/s)t ]\hat{i} - (1/3 N/s2)t2 \hat{j}


(a)
\vec{F}(t) = m\vec{a}
\vec{F}(3)/4 kg = \vec{a}

Use \vec{V}f = \vec{V}0 + \vec{a}t

\vec{V}f = 21/8 \hat{i} - 3/4 \hat{j}





(b)
just look at the \hat{j} component of the vector

\vec{F}j(t)/ 4kg = \vec{a}j
Use \vec{V}f = \vec{V}0 + \vec{a}t

0 = 3m/s\hat{j} - \vec{a}jt

t = 3.30 s





(c)
\vec{F}(t)/ 4kg = \vec{a}(t)

actually, now when I'm rewriting it, I'm not sure how to integrate \vec{a}

do i integrate the acceleration from 0 to 6? i don't think so...

i integrated acceleration (not accounting for C) and then integrated velocity from 0 to 6 (this is obviously wrong now that I'm looking over it)
 
Physics news on Phys.org
Find the velocity and acceleration along i and j directions separately.
Using proper kinematic equations find the remaining answers by using vector addition.
 
rl.bhat said:
Find the velocity and acceleration along i and j directions separately.
Using proper kinematic equations find the remaining answers by using vector addition.

Hi

which part are you talking about?
 
Voi = 2 m/s, F1i = 1N. Find a1i.
Similarly find Voj, F2j and a2J.
Calculate Vfi and Vfj after 3 s.
 

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