Confused about Compressed Water in Constant Pressure Process?

AI Thread Summary
To determine the heat required to convert 2 kg of compressed water at 50°C to superheated steam at 200°C under constant pressure at 1 bar, the specific internal energy values and volume calculations are essential. The internal energy of superheated steam (u2) is given as 2659 kJ/kg, while the initial internal energy (u1) for compressed water needs to be identified, likely through steam tables. The work done in the process can be calculated using the formula W = -P(V2 - V1), where specific volumes must be determined. The relationship Q + W = U2 - U1 will help in finding the heat added (Q). Understanding steam tables and specific volume calculations is crucial for solving this problem accurately.
craglyboy
Messages
8
Reaction score
0

Homework Statement


In a constant pressure process ant 1 bar determine how much heat must be added to raise the temperature of 2kg of compressed water at a temp of 50C so that it become superheated steam at a temp of 200C?

u2=2659KJ/Kg

Homework Equations


W=-P(V2-V1) Q+W=U2-U1


The Attempt at a Solution



Not really sure how to work out the volumes and struggling with how to find u1 as its compressed water.

Do i find out the volumes by attaining the specific volume and multiplying by the mass
 
Physics news on Phys.org
Ever heard of steam tables?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top