Congruence with numbers with exponents on top of exponents

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The discussion revolves around calculating the expression 2 + 3^2 + 5^3 + (3^(2*5))^3 in Z15. Participants clarify the interpretation of the expression and emphasize the importance of reducing large numbers through modular arithmetic. One user suggests using a calculator to evaluate 3^(10) and find its congruence modulo 15, noting that the resulting number is manageable. There is confusion about the size of the numbers involved, with some suggesting that the calculations are feasible with modern calculators. The thread highlights the need for effective techniques to handle large exponents in congruence problems.
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Homework Statement



Calculate 2 + 3^2 + 5^3 + 3^2*5^3 in Z15
(That last group of numbers means 3 to the 2*5 power then take this answer to the third power, It just did not paste like that)

Homework Equations





The Attempt at a Solution



2+9+5+3<--the 3 is a random guess, because I am totally lost what do to do with this last number.
I am doing this problem for independent study off of a website and it says the answer is 9, which means the last answer must be 8. How do you deal with congruence when there are such large numbers with multiple exponents like those created by the last sequence of numbers in the problem (3^2*5^3, which means take 3 to the 2*5 power then take this answer to the third power)) ?

 
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First off, just to clarify, you do mean 2 + 3^2 + 5^3 + (3^{2*5}) ^ {3} in Z_{15}, right?
 
If this is so, then you should know at least what (3^{2*5})^{3} evaluates to...
 
My problem is that I cannot figure out what the above number evaluates to congruence wise. It is so huge when you figure it up that it will not fit into a calculator. Is their some procedure to shrink this number or these exponents down to size, or figure out how the number compares to the mod by looking at?
 
morrowcosom said:
My problem is that I cannot figure out what the above number evaluates to congruence wise. It is so huge when you figure it up that it will not fit into a calculator. Is their some procedure to shrink this number or these exponents down to size, or figure out how the number compares to the mod by looking at?

The EE button on your calculator might be useful here.
http://mathforum.org/library/drmath/view/54346.html
 
Just the caculator that comes with "Windows" gives 3^{2*5}= 3^{10}= 59049, not all that big! Find what that is congruent to modulo 15 and raise that to the 3 rd power.

(For that matter, \left(3^{10}\right)^3 is NOT too big to be done exactly on any decent calculator.)
 
Maybe he means 3^{2.5^3} ? This would explain why it's too big for his calculator, because(310)3\approx10^14 should be doable for any calculator made in this millenium :wink:

morrowcosom said:
It is so huge when you figure it up that it will not fit into a calculator.
 
morrowcosom said:
(That last group of numbers means 3 to the 2*5 power then take this answer to the third power, It just did not paste like that)

That's what he said, so I'm assuming that we were on the right track.
 
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