Conical Pendulum: Period and Tension Calculation

AI Thread Summary
To calculate the period of a conical pendulum and the tension in the string, the mass (4.35 kg) is attached to a 5.50-meter string at a 64-degree angle. The tension in the string is calculated using T = (mg)/cos(θ), resulting in approximately 97.35 N. The radius of the bob's circular path is determined to be about 4.94 m. The speed is found using Tsin(θ) = (1/2)(mv²)/radius, yielding a velocity of approximately 14.1 m/s. Finally, the period is calculated as 2.2 seconds, confirming the time for one complete revolution.
tachu101
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Homework Statement



Conical Pendulum Question

Mass (m) is attached to the ceiling by a String of Length (s)
The string makes an angle of (\theta) with the vertical

Compute the Period of Revolution and the Tension in the string?

Mass of Bob (m) -- 4.35kg
Length of String (s) -- 5.50 meters
\theta -- 64 degrees

Homework Equations



1/2(mv^2)/radius -- Centripetal Force

W= mg -- weight

Not sure what else I need

The Attempt at a Solution



I think that the tension in the string would be

Tcos(\theta)=mg ---- T=(mg)/cos(\theta)

So

(4.35)(9.81)/cos(64)= ---- 97.35 NI have no idea how to get the period though, but I think it has to do with

Tsin\theta= 1/2(mv^2)/radius
 
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So far, so good.

Once you find the speed you can use that to find the period. What's the radius of the bob's path?
 
I think that the radius would be

string length --- (s) sin (Theta) --- so 5.5sin(64)= 4.94m

I am not sure the equation to find the period though?

I have radius, string length, tension in string, and mass of the Bob.
 
tachu101 said:
I think that the radius would be

string length --- (s) sin (Theta) --- so 5.5sin(64)= 4.94m
Good.
I am not sure the equation to find the period though?
The period is just the time the bob takes to make one complete revolution. Find the speed (and figure out the distance).
 
Would I find the speed by using Tsin(theta)= (1/2)(mv^2)/radius ----

97.35 sin (64) = (1/2)(4.35)(v^2)/(4.94) ----- velocity = 14.097 m/sec ?so the distance would be (2)(radius)(pi)= (2)(4.94)(pi)= 31.03m

I am stuck now on how to find the period. Is there a certain equation that is used to find the period, we just started this topic?
 
tachu101 said:
Is there a certain equation that is used to find the period, we just started this topic?
How about distance = speed x time?
 
So (2)(pi)(r)=(velocity)(time)

thus

31.03m=(14.1m/sec)(t) ---- so ---- period= 2.2 sec?
 
Sure. It's just the time required for one revolution. You have the distance and the speed--that's all there is to it.
 
thank you so much for the help, I am going to go back and check all of my work.
 

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